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mt of Odor- free water For example ml of Sample 125 25 0 50 0 100 200 Table 3 Sample Odor Series Observer Response· 1 2 3 4 5 EB +EB EB+ + + + EB EB + +++++ 188 175 200 150 200 100 0 *CIrcled plus equals threshold level 8 3 2 Obtam mdividual threshold odor numbers from Table 1 Observer T O N 14 28 32 42 58 8.3 3 The geometnc mean IS equal to the nth root of the product of n numbers Therefore 4 x 8 x 2 x 2 x 8 = 1,024 and Y/ 1,024 = log 1,024 = 3 0103 = 06021 5 -S- andanti-logof06021 =4=TON For lDstance mt sample dtluted to 200 m1 Response threshold 63 125 o 25 50 100 + +++ t Threshold 83 CalculatlOns of panel results to find the most probable average threshold are best accomplIshed by appropnate statIstIcal methods For most purposes, the threshold of a group can be expressed as the geometnc mean of the mdlVldual thresholds The geometnc mean IS calculated m the followmg manner 8 3 1 Obtam odor response as outlmed m Procedure and record results 140 1-6PDF Image | Methods for Chemical Analysis of Water and Wastes
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