Fuel Cell Handbook (Seventh Edition)

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Fuel Cell Handbook (Seventh Edition) ( fuel-cell-handbook-seventh-edition )

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x = − b ± b2 − 4ac = − 0.8012 ± (0.8012)2 − 4(0.426)(0.0666) = - 0.0873 and - 1.794 2a The only root that is physically possible is x = -0.0873. The following table summarizes the effect of accounting for the water gas shift equilibrium: 2(0.426) mol percent FC outlet Gas w/o shift. CO 0.00 CO2 33.33 H2 20.00 H2O 46.67 Total 100.00 Spent Fuel Effluent Calculation Lb mol/hr, assuming 100 lb mol/hr basis Mol percent FC outlet in shift equil. 8.73 24.61 11.27 55.39 100.00 FC outlet w/o shift 0.00 33.33 20.00 46.67 100.00 Effect of shift rxn -(-8.73) -8.73 -8.73 -(-8.73) 0.00 FC outlet in shift equil. 8.73 24.61 11.27 55.39 100.00 Example 9-7 Generic Fuel Cell - Determine the Required Cell Area and Number of Stacks Given a desired output of 2.0 MWDC and the desired operating point of 600 mV and 400 mA/cm2, (a) How much fuel cell area is needed? (b) Assuming a cell area of 1.00 m2 per cell and 280 cells per stack, how many stacks are needed for this 2.0 MW unit? Solution: (a) Recalling that power is the product of voltage and current, first determine the total current for the fuel cell as P ⎛2.0MW⎞⎛106 W⎞⎛1VA⎞⎛ 1kA ⎞ I = V = ⎜⎝ 0.600 V⎟⎠⎜⎝1 MW⎟⎠⎜⎝ 1 W ⎟⎠⎜⎝1000 A⎟⎠ = 3,333 kA Because each individual cell will operate at 400 mA/cm2, determine the total area as I ⎛ 3,333 kA ⎞⎛1000 mA⎞⎛1000 A⎞ 2 Area = Current Density = ⎜⎝ 400 mA / cm2 ⎟⎠⎜⎝ 1 A ⎟⎠⎜⎝ 1 kA ⎟⎠ = 8,333,333 cm b) The number of required cells and stacks are calculated simply as No. of Cells = No. of Stacks = 1 m2 per cell ⎜⎝ 10,000 cm2 ⎟⎠ = 833 cells () 8,333,333 cm2 2 ( )⎛1m⎞ (833 cells) = 2.98 stacks ≅ 3 stacks (280 cells per stack) 9-12

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