Structured Zeolite Adsorbents for PSA Applications

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monolith. Narrower widths of the breakthrough fronts were also observed at 0.5 or 1 l/min for sample C5*1h20min (ca. 7 or 6 s) than for the uncoated monolith (12 or 9 s), respectively. The time to reach 5% of the final concentration is about half of sample C5*1h20min (72 s), although sample G9 shows the highest zeolite loading (0.064 g/g, see Table 1) and thus has the highest adsorption capacity, The short time to reach 5% of the final concentration despite the high zeolite loading for sample G9 is most likely due to a gas velocity distribution across the monolith channels in this sample, due to sediments on top of the film, implying that the experimental curve originates from a convolution of different breakthrough fronts from different channels experiencing diverse flow rates. The width of the breakthrough profile is about 140 s for sample G9. The greater width of the breakthrough curve, is an indication of higher resistance to mass transfer (in the sediments). As pointed out above, the main fraction of zeolite in this sample is in the form of relatively large sediments with long diffusion paths. Figure 8 (b) shows the carbon dioxide breakthrough profiles measured at 1 l/min. The curves show a similar trend as at 0.2 l/min, with the difference that the time to reach 5% of the final concentration is shorter and the width of the breakthrough curves are smaller due to faster saturation of the zeolite at the higher flow rate. 3.5.2 Quantitative interpretation of CO2 breakthrough profiles As described above, the results from SEM and liquid nitrogen sorption suggest that the diffusion paths may be different in the NaX film samples studied in this work. Figure 9 shows a schematic representation (not drawn to scale) of the film samples C5*1h20min and G9, in concert with SEM and N2 sorption results. Sample C5*1h20min consists of a 1.5 m thick zeolite film of slabs of intergrown crystals with closed grain boundaries. The slabs are separated by some open grain boundaries and there are no sediments on top of the film. The diffusion length may be thus assumed to be the film thickness (l = 1.5 m) and equation 9 should be used to estimate the effective diffusivity De from the mass transfer coefficient k. 79

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