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m ⎛ =⎜2.858 kA⎞⎛0.08291lbH ⎞ ⎟⎜ 2 ⎟(500cells)=118.4 lbH hr 2 H2 ,consumed cell ⎠⎝ hr - kA ⎠ Thus, the reader may find it more expedient and less error prone to envision parallel arrangement ⎝ when calculating the mass flow requirement of hydrogen. (b) The utilization of fuel in a fuel cell is defined as Uf = H2, consumed H 2,in Therefore the fuel flow rate required to generate 1 MWDC can be calculated as n ⎛ =⎜118.4 lbH ⎞⎛ 1lbmolH ⎞⎛1lbmolO ⎞ 2⎟⎜ 2 ⎟⎜ 2⎟=29.38 lbmolO hr 2 Uf 80% lbH H 118.4 lb H2 H2,in = 2,consumed = hr =148.0 hr2 (c) To determine the air requirement, first observe that the stoichiometric57 ratio of hydrogen to oxygen is 2 to 1 for H2O. Thus, the moles of oxygen required for the fuel cell reaction are determined by O2 , consumed ⎝ ⎜ ⎟⎜ ⎟ hr ⎠⎝2.0158lbH2 ⎠⎝2lbmolH2 ⎠ If 25 percent utilization is required, then the air feed must contain four times the oxygen that is consumed n ⎛ = ⎜ 29.38 lb mol O consumed ⎞⎛ 1lb mol O 2 ⎟⎜ 2 supplied ⎞ ⎟ = 117.5 lb mol O hr 2 O2 , supplied ⎝ ⎜⎟ hr ⎠⎝0.25lbmolO2 consumed⎠ Because dry air contains 21 percent O2 by volume, or by mole percent, the required mass flow rate of dry air is ⎛ mair,supplied =⎜117.5 lbmolO supplied⎞⎛ 1lbmolair ⎞⎛28.85lbdryair⎞ lbdryair 2 ⎟⎜ ⎟⎜ ⎟=16,142 ⎝ hr ⎠⎝0.21lbmolO2 ⎠⎝ 1lbmolof air ⎠ hr Example 9-3 PAFC Effluent Composition A PAFC, operating on reformed natural gas (900 lb/hr) and air, has a fuel and oxidant utilization of 86 percent and 70 percent, respectively. With the fuel and oxidant composition and molecular weights listed below, how much hydrogen will be consumed in lb mol/hr? (b) How much oxygen is consumed in lb mol/hr? (c) What is the required air flow rate in lb mol/hr and lb/hr? 57 The stoichiometric ratio is the ratio of atoms in a given molecule. 9-3PDF Image | Fuel Cell Handbook (Seventh Edition)
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