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As Equation 1.22 shows, the bed thickness (tb, ft) is the quotient of the bed volume (Vb) and the bed cross-sectional area (Ab). For a 30 lb/ft3 carbon bed density, this becomes V b 0 . 0 3 3 3 M c' tb A A bb (For vertically erected vessels, Ab = Q/Vb, while for horizontally erected cylindrical vessels, A = LD.) Once ∆Pb is known, the system fan horsepower requirement (hpsf) can be calculated: (1.31) (1.32) where hp 2.50104QP sf s gas volumetric flow through system (acfm) total system pressure drop = ∆Pb + 1 Q = ∆Ps = (The extra inch accounts for miscellaneous pressure losses through the external ductwork and other parts of the system.[9]10 However, if extra long duct runs and/or preconditioning equipment are needed, the miscellaneous losses could be much higher.) This equation incorporates a fan efficiency of 70% and a motor efficiency of 90%, or 63% overall. The horsepower requirement for the bed drying/cooling fan (hpcf) is computed similarly. While the bed fan pressure drop would still be ∆Pb, the gas flow and operating times would be different. For typical adsorber operating conditions, the drying/cooling air requirement would be 50 to 150 ft3/lb carbon, depending on the bed moisture content, required temperature drop, and other factors. The operating time (θcf) would be the product of the drying/cooling time per desorption cycle and the number of cycles per year. It can be shown that: (1.33) N cf 0.4D A s A (The “0.4” allows for the fact that as a rule-of-thumb, approximately 40% of the desorption cycle is used for bed drying/cooling.) The cooling water pump horsepower requirement (hpcwp) would be computed as follows: 2.52104qcw Hs (1.34) 10To obtain a more precise estimate of ductwork pressure drop, refer to Section 2 of this Manual. 1-29 hp cwpPDF Image | Carbon Adsorbers
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